ALTCAR EXPO Santa Monica CA 2008
This low power test was done in
an effort to prove that the
accelerating flywheel and turbine
driving it, is not a load on the
input electric power. 100 watts is
applied to the bottom suction
blower, which spins at a constant
rpm. This is when the flywheel is
released and it accelerates at a
constant rate. However, the
power meter on the blower shows
no additional power use during
the flywheel acceleration! All the
electric input power is going to
the air being shot out the exhaust
ring (clear plastic). The
atmosphere alone powers the
flywheel storing greater amounts
of energy per second. The
exhaust is blowing out to free air
or 0.00 inches of water or better,
it does not work against
atmospheric psi. It is removing
cfm air mass only . The
atmosphere will automatically
replace this exhaust air via
natural air pressure at 14.7 psi,
expanding and moving as artificial
wind into the device’s open
intake. This is how energy from
the atmosphere is harnessed by
the technology in this test.
an effort to prove that the
accelerating flywheel and turbine
driving it, is not a load on the
input electric power. 100 watts is
applied to the bottom suction
blower, which spins at a constant
rpm. This is when the flywheel is
released and it accelerates at a
constant rate. However, the
power meter on the blower shows
no additional power use during
the flywheel acceleration! All the
electric input power is going to
the air being shot out the exhaust
ring (clear plastic). The
atmosphere alone powers the
flywheel storing greater amounts
of energy per second. The
exhaust is blowing out to free air
or 0.00 inches of water or better,
it does not work against
atmospheric psi. It is removing
cfm air mass only . The
atmosphere will automatically
replace this exhaust air via
natural air pressure at 14.7 psi,
expanding and moving as artificial
wind into the device’s open
intake. This is how energy from
the atmosphere is harnessed by
the technology in this test.
This same device is designed to output 60kw @1000cfm but is being tested in iterations for data and safety.
Recent tests show that existing blower would need to be replaced with a blower which draws 1000 cfm @ 34.6 in
wg @ (10 hp or less). The blower used now is not the correct type,it is too inefficient. However, the tests are
correct; the energy output is free.
At maximum intake wind speed of 500mph @ 1000 cubic feet per minute, this flow can yield 60kw by the output
turbine. The artificial wind is driven by the natural atmospheric pressure converting to high velocity (kinetic
energy) flow, by virtue of the Bernoulli effect. The low pressure (34.6 in wg suction) source is a 7,500 watt,
blower, which evacuates 1000 cfm to open air. This test has not yet been done but the wind power formulas
predict it and so far the device has matched the formulas predictions.
The device is an aerodynamic lift force device not a pressure differential linear pneumatic device.
Wind power formula
Wind power only depends on the wind speed and
density and is independent of the turbine type or size.
Wind power only depends on the wind speed and
density and is independent of the turbine type or size.
Former Governor of New York
Mr George Pataki
see this video on youtube soon
Mr George Pataki
see this video on youtube soon
Incontrovertible evidence
In the 100watt test ,additional data has been gathered.In the case of the blower motor before and during the
flywheel release,the power factor PF of the input electric power and the rpm behavior were monitored. The PF
remained between .89 and. 90 before and during flywheel acceleration and the rpm remained at 3072 throughout
the test. Hence the flywheel does not effect the blower in any way nor does it add any electrical load. Also,
the flywheel reached 45 joules @ 2000 rpm in about 20 sec thats 2.25 J/s or watts free output average.
However, it went from 1000rpm to 2000rpm in 3 sec! A 34 J gain.Thats 11J@1000rpm to 45J@2000rpm.
In 3sec =11.33 j/s or watts average free output. The flywheel accelerated up to 2773 rpm to a near constant V.
The free output was 11.33% as much as the electrical input during the last 3 seconds. The max energy stored was
83.74J. The turbine wind speed 53 mph @ 2773 rpm.
It is my estimation that the high V wind is losing kinetic energy and also heat energy ,due to expansion . As the High
pressure under the "power takeoff" turbine foils expands, it pushes the airfoils into the low psi above the airfoils as
lift (torque).So what is the true source of energy doing the work of the flywheel acceleration?Even if we never figure
it out, one thing is certain, the flywheel or turbine output is not an electrical load thus its free. Further,at even
higher wind velocity ,it will produce 10x and greater the electrical input. this update sept 26,09
In the 100watt test ,additional data has been gathered.In the case of the blower motor before and during the
flywheel release,the power factor PF of the input electric power and the rpm behavior were monitored. The PF
remained between .89 and. 90 before and during flywheel acceleration and the rpm remained at 3072 throughout
the test. Hence the flywheel does not effect the blower in any way nor does it add any electrical load. Also,
the flywheel reached 45 joules @ 2000 rpm in about 20 sec thats 2.25 J/s or watts free output average.
However, it went from 1000rpm to 2000rpm in 3 sec! A 34 J gain.Thats 11J@1000rpm to 45J@2000rpm.
In 3sec =11.33 j/s or watts average free output. The flywheel accelerated up to 2773 rpm to a near constant V.
The free output was 11.33% as much as the electrical input during the last 3 seconds. The max energy stored was
83.74J. The turbine wind speed 53 mph @ 2773 rpm.
It is my estimation that the high V wind is losing kinetic energy and also heat energy ,due to expansion . As the High
pressure under the "power takeoff" turbine foils expands, it pushes the airfoils into the low psi above the airfoils as
lift (torque).So what is the true source of energy doing the work of the flywheel acceleration?Even if we never figure
it out, one thing is certain, the flywheel or turbine output is not an electrical load thus its free. Further,at even
higher wind velocity ,it will produce 10x and greater the electrical input. this update sept 26,09
Sept 26,2009
A side note: Simple logic will reveal that if 100% of the electrical input energy is accounted for by the
blower (blowing out air mass + losses) and yet additional work energy is being measured in the
flywheel then there must be some other source of energy being harnessed.
blower (blowing out air mass + losses) and yet additional work energy is being measured in the
flywheel then there must be some other source of energy being harnessed.
Test Discription
Click the image video link